### If you’ve moved beyond the basics of Scuba diving, and have started planning your own, independent dives, you should know you Surface Air Consumption, or SAC.

It could save your life.

It’s happened to me more times than I’d like to admit; running low on air during a dive. OK, it has actually only happened once where it was critical, but I have had a few close shaves in addition to this. The one time was during a dive in Egypt, where we needed to exit through a small cave.

But I had misjudged condition on the dive going further into the cave than I should have before turning around. So as we were suspended on a safety stop line inside the cave, my manometer mercilessly ticked away towards zero.

Luckily, I had my buddy close by, and I was able to use his octopus while we finished our safety stop and surfaced.

## After that, I learned my SAC’s

Surface Air Consumption is an expression of your air consumption during dive, with the depth of the dive taken out of the equation. As we all know, air consumption increases with depth due to the pressure increases the density but reduces the volume of the air we breathe (as per Boyle’s Law).

So simply looking at our manometer doesn’t tell us the whole story, as we can consume more air during a 30-minute dive to 35 meters than we do during a 1-hour dive to 8 meters.

When we know our SAC, we can make estimations as to how much air we will likely use during a dive to any given depth, allowing us to factor air consumption into our dive planning.

Calculating your SAC isn’t that difficult, and is part of most solo diving and technical diving courses.

## Do some measuring

First, do a number of dives at different depths and conditions. For each of these dives, note down the depth, time, gas used, and cylinder size.

Ideally, include a dive where you were really strained due to currents, or swim for 5 minutes at maximum effort during a dive. Then make note of the air consumed in those 5 minutes, to also have an idea of your air consumption while working under strain.

## Do the math

Once you have these numbers, you can start your calculations. While there are a number of internet sites where you can simply punch the numbers into boxes and get an answer, I find it useful to be able to do the calculations yourself.

## Metric system

The calculations go as follows:

VT x VC / T / P = SAC

Where VT is Total Volume of the cylinder used in liters, VC is Consumed Volume in bars during the dive, T is duration of the dive, P is the pressure in bars of the average depth of the dive (or maximum depth if you stayed at the same depth the entire dive), and SAC is the Surface Air Consumption in liters per minute.

An example: You do a dive to an average of 20 meters with a 15 liter tank that is filled to 200 bars at the start of the dive. You finish the dive with 150 bars after 20 minutes of diving. The equation would then look like this:

### VT = 15 liters

### VC = 50 bars

### T = 20 minutes

### P = 3 (20 meters of water equals 3 bars of pressure)

### So… 15 x 50 / 20 / 3 = 12.5 liters per minute

Now I know that I consume 12.5 liters per minute at the surface. For any given subsequent dive, I can now simply time this number with the intended depth and time to see how much air I’ll need for that dive.

For the maximum strain test, do the same calculation, with 5 minutes as the dive time.

## A few examples:

- A dive of 45 minutes to 25 meters: 12.5 x 45 x 3.5 = 1969 liters of air
- A dive of 1 hour to 10 meters: 12.5 x 60 x 2 = 1500 liters of air
- A dive of 30 minutes to 35 meters: 12.5 x 30 x 4.5 = 1687.5 liters of air

Needless to say, in all three of these examples, I should be returning to the surface with at least 50 bars of air left in my cylinder, so I would need to add that to the number.

So to take the first dive as an example, before jumping in to do the dive, I should make sure that I have a cylinder with at least 2019 liters of air in it. For a 12 liter cylinder, that I would consume 169 bars of air. So to do this dive safely, I would need a full 12 liter cylinder, filled with 200 bars of air.

## Imperial system

For the imperial system, the formula gets a little trickier, but still easy, once you the grasp of it. It goes as follows:

R x PsiC / WP / T / P

R is the cylinger rating in cubic feet, PsiC is the Psi consumed, WP is for Working Pressure, the rated pressure that the tank operates under, T is the time in minutes, and P is the pressure at the average depth of the dive, or maximum if you’ve stayed at the same depth the entire dive.

An example: I’ve done a dive to 66 feet for 35 minutes, with an 80 cubic feet cylinder with a working pressure of 3000 Psi (both can be found on the cylinder), I have consumed 2000 Psi of that air. So the numbers would be:

### R = 80 cubic feet

### PsiC = 2000 Psi

### WP = 3000 Psi

### T = 35 minutes

### P = 3 (pressure at 66 feet)

### Or… 80 x 2000 / 3000 Psi / 35 / 3 = 0.5 psi of air pr. minute

Of course, the SAC rates above are based on a single dive, and seeing as a number of factors can influence air consumption.

It’s best to do a series of dives, as mentioned, and calculate the SAC for each, then taking an average of those dives. And by doing the strain test mentioned earlier as well, you will have your SAC both for general diving and for strenuous conditions.

Also note that our SAC tends to change a bit over time, depending on our experience level, how streamlined we are, finning technique, and physical fitness.

So redo the calculation every now and again. I typically do it once a year, or anytime I haven’t gone diving in a while.

Know you SAC’s, and never risk running out of air again!

Hi Thomas – this is a useful attempt at outlining this subject for the uninitiated. However, with respect I have to point out two basic errors.

Firstly, the parameter you have called “VC” and described as “Consumed Volume in bars” is a pressure, not a volume.

That parameter is better described as “the pressure reduction in the tank, measured in bars, due to gas consumption”.

Secondly, in arithmetical terms the formula you give of

VT x VC / T / P = SAC

is ambiguous. To be clear, it needs to be expressed as

SAC = (VT x VC) / ((T x P)

and of course having identified VC as a pressure, rather than a volume, it might be better to express it using a letter other than “V”.

I don’t mean to nit pick, but these are fundamental errors which would be be very confusing to someone trying to use this article to get their head around SAC rates for the first time.

Hi John, as of the rules of BIDMAS, it doesn’t matter whether you multiply or divide something first and the equation above doesn’t need any brackets.

There is no mathematical error here, fundamental or otherwise. Actually your equation is wrong because it has an extra, open bracket.

Thanks Thomas for the calculation, very useful for newby diver (not newby mathematician) 🙂

I don’t understand how you add 50 bar directly to the litres to calculate total air needed. Isn’t it should be convert to Lt first e.g 50 X 12lt = 600 Lt add 1,969lt in example dive 1. Instead of needing 2,019 it should be 2,560lt

How long would 1 3.0 cubic feet (3,000 PSI) tank last if I stayed under water at about a 5 foot depth?

Zsuzsanne well it does need brackets as he made it clearer as he said! and ofcourse its useful for newby divers thats the point. If i knew this by birth i wouldnt lookup to read about it (in a clear way). as a science student i can see the errors and i find what john did is a great job correcting fundemental errors…he didnt say there is a mathamtical error but a volume is not a pressure lol (basic common sense i guess?) and the equation is confusing for newby divers who dont study any science and looking for information. so your argument is pointless newby mathematician. have a great day Thanks thomas for the information and thanks john for pointing some mistakes.

by the way if you put thomas equation in some calculators it will 100% comes out wrong as if it matters for the calculator to know what are you dividing on first… so basically in thomas equation the pressure will be multiplied with the volumes and then divided on the time for many calculators this is the case.

extra bracket is an Obvious mistake (not meant to be ofc)

I thought 20 meters of water would only be 2 bar ????.

Every 10 meters being 1 bar of pressure.

Correct me if I’m wrong please.

Hi Craig,

Yes, 1 bar for every 10 meters(33 feet) of water. However, there’s also a pressure of 1 bar at the surface. So, 1 bar at the surface + 2 bars from the 20 meters of water = 3 bars pressure.